One way to find an equation for a line tangent to the graph of a function is to assume that the function and the tangent line have the same formula.
Suppose f(x) = sin(2x) + 3cos(x). (Define f this way on your calculator.)
Suppose we want to find an equation for the line tangent to the graph of f at (0, f(0)).
First observe that any line has an equation like y = ax+b.
If the function
and its tangent line have the same formula, we have ax+b = f(x).
(Enter this
equation on your calculator and store
it in some convenient place, such as z. Don't forget the multiplication
symbol between the a and the x.)
To find b, set x = 0. (Store the resulting value in b and look at the equation again.)
Since the
graph of f really
isn't a straight line, we can't expect
to solve for a and get a number. The next best idea is to solve
for a and set
x=0. (We really only
expect good results near the point of tangency.) Alas, that doesn't work
either with this problem. But if we take derivatives
first and then set x = 0, everything works
fine.
One way to find an equation for the best quadratic approximation to a function is to assume the function and the parabola have the same formula.
Start a new problem, and define f(x) = sin(2x) + 3cos(x). We want to find a good quadratic approximation to f near the point (0, f(0)).
Any quadratic
equation has a formula of the form ax2 + bx + c.
If the quadratic
approximation is perfect, we'll have ax2 + bx + c = f(x).
(Enter this
equation on your calculator and store
it in some convenient place, such as z. Don't forget the multiplication
symbols after the a and the b.)
To find c, set x = 0. (Store the resulting value in c and look at the equation again.)
To find b, differentiate first, and then set x = 0. (Store the resulting value in b and look at the equation again.)
How can you
find a?
Exercises