Calculus Project #32 Taylor Polynomials
 

One way to find an equation for a line tangent to the graph of a function is to assume that the function and the tangent line have the same formula.

Suppose f(x) = sin(2x) + 3cos(x). (Define f this way on your calculator.)

Suppose we want to find an equation for the line tangent to the graph of f at (0, f(0)).

First observe that any line has an equation like y = ax+b.

If the function and its tangent line have the same formula, we have ax+b = f(x).
(Enter this equation on your calculator and store it in some convenient place, such as z. Don't forget the multiplication symbol between the a and the x.)

To find b, set x = 0. (Store the resulting value in b and look at the equation again.)

Since the graph of f really isn't a straight line, we can't expect to solve for a and get a number. The next best idea is to solve for a and set x=0. (We really only expect good results near the point of tangency.) Alas, that doesn't work either with this problem. But if we take derivatives first and then set x = 0, everything works fine.
 
 
 

One way to find an equation for the best quadratic approximation to a function is to assume the function and the parabola have the same formula.

Start a new problem, and define f(x) = sin(2x) + 3cos(x). We want to find a good quadratic approximation to f near the point (0, f(0)).

Any quadratic equation has a formula of the form ax2 + bx + c.
If the quadratic approximation is perfect, we'll have ax2 + bx + c = f(x).
(Enter this equation on your calculator and store it in some convenient place, such as z. Don't forget the multiplication symbols after the a and the b.)

To find c, set x = 0. (Store the resulting value in c and look at the equation again.)

To find b, differentiate first, and then set x = 0. (Store the resulting value in b and look at the equation again.)

How can you find a?
 
 

Exercises

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