1. A squadron of bombers is attempting to destroy an ammunition depot
that has a rectangular shape and is 1250 meters by 950 meters. The
bombing run will proceed down the long center axis of the depot.
If a bomb lands anywhere on the depot, a hit is scored. Otherwise,
the bomb is a miss. There are 5 bombers in each squadron, each carry
1 bomb. The aim point is the center of the depot. The point
of impact is assumed to be independent and normally distributed around
the aim point with a standard deviation of 600 meters in the down range
direction and 300 meters in the cross range direction.
(a) Find the expected number of hits in one run by a squadron.
(b) Simulate the operation and obtain an estimate of the expected number
of hits in one run by a squadron. Use the following random number
streams.
|
stream
1
|
0.089
|
0.821
|
0.609
|
0.540
|
0.558
|
0.733
|
0.788
|
0.671
|
0.588
|
|
stream
2
|
0.629
|
0.823
|
0.862
|
0.631
|
0.019
|
0.774
|
0.890
|
0.885
|
0.647
|
2. Suppose a simulation was performed 20 times to obtain an estimate of the parameter X. The average and sample standard deviation of the observed values was calculated to be 1.414 and 0.011, respectively. Estimate the number of runs that must be done in order that the standard error does not exceed 0.001.
3. For an upcoming mission, a wave of 5 aircraft is to be launched from an aircraft carrier. The aircraft will be launched using two available catapults. The time to launch an aircraft is normally distributed with a mean of 7 minutes and a standard deviation of 2 minutes. Approximately 20% of the time a mechanical failure is found on an aircraft before it is launched. For this reason, 2 aircraft are on standby, and the time to launch one of these aircraft is normally distributed with a mean of 10 minutes and a standard deviation of 3 minutes. The time to discover that an aircraft has a mechanical failure and cannot be launched is exponentially distributed with mean of 4 minutes. Should it happen that it is impossible to launch 5 of the 7 aircraft, the mission will be canceled and will be considered as a failure. Simulate the launch of one wave of 5 aircraft and obtain an estimate of the time required to launch the wave.
| aircraft | 1 | 2 | 3 | 4 | 5 | 6 | 7 |
| random number | .83 | .18 | .24 | .49 | .46 | .22 | .61 |
| failure? | no | yes | no | no | no | no | no |
Now simulate time to launch and failure detection.
Time until aircraft 2's failure is discovered is generated using the exponential distribution generator tfail = -4 ln(R). The random number generated is R = .45, so tfail = 3.19 min.
Time to launch is generated using the Standard Normal Tables and t = 7 + 2R.
aircraft 1 3 4 5 6 random number .16 .70 .79 .51 .59 Z -1.00 .53 .81 .03 .23 time to launch 5.00 8.06 8.62 7.06 7.46 Launch from cat #1: 1, 2 (failed), 3 for time of 5.00 + 3.19 + 8.06 = 16.25.
Launch from cat #2: 4, 5 for time 8.62 + 7.06 = 15.68.
Aircraft #6 is then launched from cat #2, making the total launch time 15.68 + 7.46 = 23.14.
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last update: 05 January 2000