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Factoring
over
In other words, we shall express
as a product of
irreducible polynomials having coefficients in
.
This is harder - the constraint
``having coefficients in
'' is more restrictive
than ``having coefficients in
''.
First, let us consider some examples:

is already irreducible.

-
is the factorization into
irreducibles over
.

-
is the factorization into
irreducibles over
.
Exercise 2.12.7
Show

is irreducible over

.

-
is the factorization into
irreducibles over
.
Exercise 2.12.8
Show

is irreducible over

.
In general, we have a ``formula'' for the
irreducible factors of
. To state this we need a definition.
Definition 2.12.9
Let

be the prime factorization of
an integer

. Define the
Möbius function

by:

and, if

then
For each

, define
the
cyclotomic polynomial
by
Since cyclotomic polynomials are useful for the
construction and theory of finite fields, they are
also important in algebraic coding theory.
Theorem 2.12.10
For each

,

is irreducible over

.
For the proof, which goes beyond the scope of this book, see
Lang [La], Ch VIII, §3, or Theorem 6.5.5 of Herstein [Her].
Theorem 2.12.11
We have
where

is as above.
This follows from the Möbius inversion formula
(see Lidl, Pilz [LP], Ch. 3, §13).
Example 2.12.12
According to this theorem,

,
where

,

,
and

.
This is the same result as the calculation ``by hand'' above.
Exercise 2.12.13
Show

.
More generally, show that for any prime

,

.
Exercise 2.12.14
Completely factor

into irreducibles over

.
Exercise 2.12.15
Completely factor

into irreducibles over

.
Exercise 2.12.16
Completely factor

into irreducibles over

.
Exercise 2.12.17
Compute

,

.
Next: Polynomials and rings using
Up: Special Project: Factoring over
Previous: Irreducibility criteria
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David Joyner
2002-08-23