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There are lots of subsets of a group
which
still have the structure of a group. These objects are
defined more precisely next.
Definition 5.8.1
Let

be a group.
A
subgroup of

is a subset

of

such that

, together with the operation

inherited as
a subset of

, satisfies the group operations (G1)-(G4)
(with

replaced by

everywhere).
Notation: If
is a group then we will denote the statement
``
is a subgroup of
" by
Theorem 5.8.3 (Lagrange)
Let

be a subgroup of a finite
group

. Then

divides

.
proof: For
, define
if
, where
This is an equivalence relation.
(The interested reader can easily verify
the reflexive, symmetry, and transitivity
properties.) Moreover, the equivalence class
of
consists of all elements in
of the form
, for some
, i.e.,
. Let
denote a complete set of representatives for the
equivalence classes of
. Because of the
cancellation law for groups,
for each
.
Furthermore, we know that the equivalence classes partition
,
so
Comparing cardinalities of both sides, we obtain
. This proves the theorem.
Definition 5.8.4
If

and

are finite groups
and

then the integer

is called
the
index of

in

,
denoted
![$ [G:H]=\vert G\vert/\vert H\vert$](img3686.png)
.
Example 5.8.5
A permutation group

generated by elements

belonging to

is a subgroup of

, i.e.,

.
Example 5.8.6
Let
This is a subgroup of

called
the
alternating subgroup of degree
.
Definition 5.8.7
The
center of a group

is the subgroup

of all elements which commute
with every element of

:
Of course, the identity element always belongs to
.
If the identity element is the only element of
then we say
has trivial center.
On the other hand,
is commutative if and only if
.
Exercise 5.8.8
For

and

as above,

is
partitioned into four disjoint sets of the form

.
Here are two of them:

and

). Find the other two.
Exercise 5.8.9
Let

be a group written multiplicatively
and let

be a subset which is closed under multiplication
and taking inverses. Show that

is a (sub)group.
Exercise 5.8.10
Show, as a corollary to the previous
Theorem
5.8.3,
that Theorem
5.7.7(b) is true.
Exercise 5.8.11
Let

be a group. Show

is a group.
Exercise 5.8.12
Let

. Determine

.
Exercise 5.8.13
Let

,

and

be subgroups of a group

.
(a) Must

be a subgroup of

? If so, prove why; if not,
give an example.
(b) Must

be a subgroup of

? Again, prove or
disprove.
(c) Must

be a subgroup?
Exercise 5.8.14
Let

. Determine

.
Exercise 5.8.15
The subset

,

, introduced in the proof of Lagrange's Theorem
5.8.3 is called a ``left coset'' of

in

.
(These shall be studied in a later section in more detail.)
Show that if

is a subgroup of

then

.
Next: Puzzling examples
Up: An introduction to groups
Previous: Permutation groups
  Contents
  Index
David Joyner
2002-08-23