{VERSION 3 0 "IBM INTEL NT" "3.0" } {USTYLETAB {CSTYLE "Maple Input" -1 0 "Courier" 0 1 255 0 0 1 0 1 0 0 1 0 0 0 0 }{CSTYLE "2D Math" -1 2 "Times" 0 1 0 0 0 0 0 0 2 0 0 0 0 0 0 }{CSTYLE "2D Output" 2 20 "" 0 1 0 0 255 1 0 0 0 0 0 0 0 0 0 } {CSTYLE "" -1 256 "" 1 18 0 0 0 0 0 1 0 0 0 0 0 0 0 }{PSTYLE "Normal" -1 0 1 {CSTYLE "" -1 -1 "" 0 1 0 0 0 0 0 0 0 0 0 0 0 0 0 }0 0 0 -1 -1 -1 0 0 0 0 0 0 -1 0 }{PSTYLE "Maple Output" 0 11 1 {CSTYLE "" -1 -1 " " 0 1 0 0 0 0 0 0 0 0 0 0 0 0 0 }3 3 0 -1 -1 -1 0 0 0 0 0 0 -1 0 } {PSTYLE "Maple Plot" 0 13 1 {CSTYLE "" -1 -1 "" 0 1 0 0 0 0 0 0 0 0 0 0 0 0 0 }3 0 0 -1 -1 -1 0 0 0 0 0 0 -1 0 }} {SECT 0 {EXCHG {PARA 0 "" 0 "" {TEXT -1 0 "" }}{PARA 0 "" 0 "" {TEXT -1 2 " " }{TEXT 256 48 " Calculus 1 optimization probl ems" }}{PARA 0 "" 0 "" {TEXT -1 0 "" }}{PARA 0 "" 0 "" {TEXT -1 22 "sm 121_optim1.mws, 7-99" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 0 "" }} }{EXCHG {PARA 0 "" 0 "" {TEXT -1 223 "Person in a boat 2 miles out fro m a straight shoreline wishes to reach a point B which is 6 miles down stream from the point A closest to shore. The boat speed is 3 mph, wal king speed is 5 mph. Find the optimal landing spot." }}{PARA 0 "" 0 " " {TEXT -1 0 "" }}{PARA 0 "" 0 "" {TEXT -1 126 "Let P be a point betwe en A and B on the shore and let x be the distance from A. Let T(x) den ote the time it takes to get to B." }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 108 "T:=x->(1/3)*sqrt(4+x^2)+(1/5)*(6-x);\nDT:=unapply(di ff(T(x),x),x);\nx0:=solve(DT(x)=0,x);\nT(x0);\nevalf(T(x0));" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%\"TGR6#%\"xG6\"6$%)operatorG%&arrowGF(,(-% %sqrtG6#,&\"\"%\"\"\"*$)9$\"\"#\"\"\"F2#F2\"\"$#\"\"'\"\"&F2F5#!\"\"F< F(F(F(" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%#DTGR6#%\"xG6\"6$%)operato rG%&arrowGF(,&*&9$\"\"\"*$-%%sqrtG6#,&\"\"%\"\"\"*$)F.\"\"#F/F6F/!\"\" #F6\"\"$#!\"\"\"\"&F6F(F(F(" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%#x0G# \"\"$\"\"#" }}{PARA 11 "" 1 "" {XPPMATH 20 "6##\"#E\"#:" }}{PARA 11 " " 1 "" {XPPMATH 20 "6#$\"+LLLL " 0 "" {MPLTEXT 1 0 57 "studen t[extrema](T(x),\{\},x );\nstudent[minimize](T(x),x );" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#<##\"#E\"#:" }}{PARA 11 "" 1 "" {XPPMATH 20 "6##\" #E\"#:" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 18 "plot(T(x),x=0..6) ;" }}{PARA 13 "" 1 "" {GLPLOT2D 400 300 300 {PLOTDATA 2 "6%-%'CURVESG6 $7S7$\"\"!$\"1nmmmmmm=!#:7$$\"1+++]#HyI\"!#;$\"1sF**3R$>%=F+7$$\"1++]( [kdW#F/$\"1a-0#o&HAgt\"F+7$$\"1++]U$e6P\"F+$\"1aF-xQ1Mq0]\"F+$\"1@L?ZLL L@F+$\"1Lo\\f?ZZ)*\\#F+$\"1y&3xYwrw\"F+7$$\"1++DEP/BEF+$\" 1%=6p>/\\x\"F+7$$\"1++](o:;v#F+$\"1j=SP$oNy\"F+7$$\"1++v$)[opGF+$\"1Y0 @P&>?z\"F+7$$\"1++]i%Qq*HF+$\"1G-xu9i,=F+7$$\"1++vQIKHJF+$\"14)GK`%37= F+7$$\"1++D^rZWKF+$\"1Fo'H?l:#=F+7$$\"1++]Zn%)oLF+$\"1MkJuF;K=F+7$$\"1 +++5FL(\\$F+$\"1E'zI?rM%=F+7$$\"1++]d6.BOF+$\"1'=_NWg[&=F+7$$\"1++vo3l WPF+$\"1\"f&ynM;m=F+7$$\"1++]A))ozQF+$\"1%pQ@!\\,z=F+7$$\"1+++Ik-,SF+$ \"1i::HF\"3*=F+7$$\"1+++D-eITF+$\"1#f1PH^O!>F+7$$\"1++v=_(zC%F+$\"1:%e ;[&[:>F+7$$\"1+++b*=jP%F+$\"1$Rf%)=E'G>F+7$$\"1++v3/3(\\%F+$\"1tzUZ4F+7$$\"1++vB4JBYF+$\"1*4wT3eW&>F+7$$\"1+++DVsYZF+$\"1\")zjQ&4w'>F+7$$ \"1++v=n#f([F+$\"1&oFi-P:)>F+7$$\"1+++!)RO+]F+$\"1$**e#*y%4&*>F+7$$\"1 ++]_!>w7&F+$\"1bAddi44?F+7$$\"1++v)Q?QD&F+$\"1Lg3n(4J-#F+7$$\"1+++5jyp `F+$\"1?3eIB4O?F+7$$\"1++]Ujp-bF+$\"1!yRCu)3^?F+7$$\"1+++gEd@cF+$\"14D ](R,Y1#F+7$$\"1++v3'>$[dF+$\"1%)>>Aj5z?F+7$$\"1++D6EjpeF+$\"1nqpw%yI4# F+7$$\"\"'F($\"1?*yn5&=3@F+-%'COLOURG6&%$RGBG$\"#5!\"\"F(F(-%+AXESLABE LSG6$Q\"x6\"%!G-%%VIEWG6$;F(Fcz%(DEFAULTG" 1 2 0 1 0 2 9 1 4 2 1.000000 45.000000 45.000000 0 }}}}{EXCHG {PARA 0 "" 0 "" {TEXT -1 57 "Find point on line y+2x=1 which is closest to the origin." }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 98 "f:=x->sqrt(x^2+(1-2*x)^2);\nDf:=una pply(diff(f(x),x),x);\nx0:=solve(Df(x)=0,x);\nf(x0);\nevalf(f(x0));" } }{PARA 11 "" 1 "" {XPPMATH 20 "6#>%\"fGR6#%\"xG6\"6$%)operatorG%&arrow GF(-%%sqrtG6#,&*$)9$\"\"#\"\"\"\"\"\"*$),&F5F5F2!\"#F3F4F5F(F(F(" }} {PARA 11 "" 1 "" {XPPMATH 20 "6#>%#DfGR6#%\"xG6\"6$%)operatorG%&arrowG F(,$*&,&9$\"#5!\"%\"\"\"\"\"\"*$-%%sqrtG6#,(*$)F/\"\"#F3\"\"&F2F2F/F1F 3!\"\"#F2F;F(F(F(" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%#x0G#\"\"#\"\"& " }}{PARA 11 "" 1 "" {XPPMATH 20 "6#,$*$-%%sqrtG6#\"\"&\"\"\"#\"\"\"F( " }}{PARA 11 "" 1 "" {XPPMATH 20 "6#$\"+cf8sW!#5" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 27 "student[minimize](f(x),x );" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#,$*$-%%sqrtG6#\"\"&\"\"\"#\"\"\"F(" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 19 "plot(f(x),x=-2..2);" }}{PARA 13 "" 1 "" {GLPLOT2D 400 300 300 {PLOTDATA 2 "6%-%'CURVESG6$7Y7$$!\"#\"\"!$\"1/X8 2[;&Q&!#:7$$!1LLL$Q6G\">F-$\"1+uc?Q!4>&F-7$$!1nm;M!\\p$=F-$\"17'H9VA>- &F-7$$!1LLL))Qj^$[F-7$$!1LLL=Kvl;F-$\"1-nuhIwSYF-7$$!1nm ;C2G!e\"F-$\"1%e<1Oo0X%F-7$$!1LL$3yO5]\"F-$\"1lI*QX2VF%F-7$$!1++]nU)*= 9F-$\"163.3X)=4%F-7$$!1LL$3WDTL\"F-$\"1u\"oU'***!#;$\"1V)G)3iVhJF-7$$!1++++0\"*H\"*Fbo$\"1#Hi1g -)pHF-7$$!1++++83&H)Fbo$\"1BOs\\'*R&y#F-7$$!1LLL3k(p`(Fbo$\"1r4%\\\"HA =EF-7$$!1nmmmj^NmFbo$\"1$o]/_d)>CF-7$$!1ommm9'=(eFbo$\"1df(zihAD#F-7$$ !1,++v#\\N)\\Fbo$\"1USLp?'z0#F-7$$!1pmmmCC(>%Fbo$\"1.L/9rs')=F-7$$!1** ***\\FRXL$Fbo$\"1E!fxKL**p\"F-7$$!1+++D=/8DFbo$\"1[#Rc:yM_\"F-7$$!1mmm ;a*el\"Fbo$\"1H`p['Q9M\"F-7$$!1pmm;Wn(o)!#<$\"1p32RU'p<\"F-7$$!1qLLL$e V(>!#=$\"1YU/e1&R+\"F-7$$\"1Mmm;f`@')Fjr$\"1ki1!y![?$)Fbo7$$\"1)****\\ 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that if 24 apple trees are planted per acre then each \+ mature tree will yield 600 apples per year on average. For each additi onal tree, the number of apples produced drops by 12 per tree each yea r. How many trees should be planted for maximum yield?" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 82 "A:=x->(24+x)*(600-12*x);\nDA:=unapp ly(diff(A(x),x),x);\nx0:=solve(DA(x)=0,x);\nA(x0);" }}{PARA 11 "" 1 " " {XPPMATH 20 "6#>%\"AGR6#%\"xG6\"6$%)operatorG%&arrowGF(*&,&\"#C\"\" \"9$F/F/,&\"$+'F/F0!#7F/F(F(F(" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%#D AGR6#%\"xG6\"6$%)operatorG%&arrowGF(,&\"$7$\"\"\"9$!#CF(F(F(" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%#x0G\"#8" }}{PARA 11 "" 1 "" {XPPMATH 20 " 6#\"&Gk\"" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 57 "student[extrem a](A(x),\{\},x );\nstudent[maximize](A(x),x );" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#<#\"&Gk\"" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#\"&Gk\"" } }}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 20 "plot(A(x),x=-5..20);" }} {PARA 13 "" 1 "" {GLPLOT2D 400 300 300 {PLOTDATA 2 "6%-%'CURVESG6$7S7$ $!\"&\"\"!$\"&SD\"F*7$$!1LL$e9r]X%!#:$\"1wEb*e%=x7!#67$$!1m;aj9$4)RF0$ \"1,m&*fvx'H\"F37$$!1LL3-=rZMF0$\"1I2xJt;=8F37$$!1LLe9w&4\"HF0$\"1>VM8 (4!R8F37$$!1n;/EXvwBF0$\"1H]H/l1f8F37$$!1L$3-))z9)=F0$\"1Y**)y')\\qP\" F37$$!1+](=n^'o8F0$\"1*ye*=-0&R\"F37$$!1JL3_+%GQ)!#;$\"1M%\\\\F-IT\"F3 7$$!1(**\\PMsh4$FU$\"18$*)o!\\AI9F37$$\"1ULL3_\"=M#FU$\"1g$oUlSsW\"F37 $$\"1vm;/wfJrFU$\"1ZBJo-kh9F37$$\"1,+]7eP_7F0$\"1=\"R6*>>x9F37$$\"1++] Pf!Qz\"F0$\"13.cda5#\\\"F37$$\"1,+](=ubJ#F0$\"1?'oSl6e]\"F37$$\"1n;zW( *Q*y#F0$\"1\"[fe7#p<:F37$$\"1NL$3F-GN$F0$\"1M#p6*y6J:F37$$\"1LLL$e'3IQ F0$\"1/q^D_*=a\"F37$$\"1,]7.Ad*F0$\"1=4/'Q+(G;F37$$\"1+]i:jf45!#9$\"1r@,%))zEj\"F37$$\"1 +DJ&>r-1\"Fit$\"1sV-7O!fj\"F37$$\"1+]P4q`;6Fit$\"17&G(f4wQ;F37$$\"1LL$ eM%4n6Fit$\"1k3XI.oS;F37$$\"1++v$4v5A\"Fit$\"1635.D0U;F37$$\"1n\"zWn*) *p7Fit$\"1cMkD>pU;F37$$\"1++DJiYB8Fit$\"16*=.#RtU;F37$$\"1Lek.Nyt8Fit$ \"1p2N>n9U;F37$$\"1+Dc^&zjU\"Fit$\"1CO2&Q$)3k\"F37$$\"1LL3-=!yZ\"Fit$ \"156I#Q1!R;F37$$\"1+D\"G8O;`\"Fit$\"1!3PUOhjj\"F37$$\"1nmm\"*\\[$e\"F it$\"1q*R6NcJj\"F37$$\"1n;aQz]O;Fit$\"17e())[6#H;F37$$\"1MekG=4*o\"Fit $\"1Dd'e!HjC;F37$$\"1++]i4TP;F37$$\"1L$3F9!z#z\"Fit$\" 1S*H]%*eOh\"F37$$\"1nmmT>KU=Fit$\"1G/RHk]2;F37$$\"1+DJqJ8&*=Fit$\"1b7: \")zH+;F37$$\"1+voa-oX>Fit$\"1-[/T;x#f\"F37$$\"#?F*$\"&Se\"F*-%'COLOUR G6&%$RGBG$\"#5!\"\"F*F*-%+AXESLABELSG6$Q\"x6\"%!G-%%VIEWG6$;F(Fgz%(DEF AULTG" 1 2 0 1 0 2 9 1 4 2 1.000000 45.000000 45.000000 0 }}}}{EXCHG {PARA 0 "" 0 "" {TEXT -1 100 "Cars crossing a 1 mile bridge are 12 fee t long and must maintain a d foot distance from each other. " }}{PARA 0 "" 0 "" {TEXT -1 120 "(a) Show that the greatest number of cars on t he bridge at a time is [5280/(12+d)], where [...] is the greatest inte ger." }}{PARA 0 "" 0 "" {TEXT -1 93 "(b) If car velocity is v mph, sho w that max traffic flow rate (in cars/hr) is [5280v/(12+d)]." }}{PARA 0 "" 0 "" {TEXT -1 147 "(c) If stopping distance (in feet) is 0.05v^2, for a car traveling v mph, and if we assume d=0.025v^2 then find spee d which maximizes traffic flow." }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 89 "f:=v->5280*v/(12+0.025*v^2);\nDf:=unapply(diff(f(v),v),v);\nv0 :=solve(Df(v)=0,v);\nf(v0[2]);" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%\" fGR6#%\"vG6\"6$%)operatorG%&arrowGF(,$*&9$\"\"\",&\"#7\"\"\"*$)F.\"\"# F/$\"#D!\"$!\"\"\"%!G&F(F(F(" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%#DfG R6#%\"vG6\"6$%)operatorG%&arrowGF(,&*&\"\"\"F.,&\"#7\"\"\"*$)9$\"\"#F. $\"#D!\"$!\"\"\"%!G&*&*$F3F.F.*$)F/\"\"#F.F9$!'+SEF8F(F(F(" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%#v0G6$$!+I-*3>#!\")$\"+I-*3>#F(" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#$\"+1&e*>[!\"'" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 57 "student[extrema](f(v),\{\},v );\nstudent[minimize](f( v),v );" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#<#,$*$-%%sqrtG6#\"\"&\"\"\" #\"\"\"F)" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#,$*$-%%sqrtG6#\"\"&\"\"\" #\"\"\"F(" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 19 "plot(f(v),v=0. .50);" }}{PARA 13 "" 1 "" {GLPLOT2D 400 300 300 {PLOTDATA 2 "6%-%'CURV ESG6$7U7$\"\"!F(7$$\"1nmmT&)G\\a!#;$\"1Q-1pX?'R#!#87$$\"1LLL3x&)*3\"!# :$\"1Q%QxvONy%F/7$$\"1+]i!R(*Rc\"F3$\"1*y)zNwpYoF/7$$\"1nm\"H2P\"Q?F3$ \"1I`J&3g3*))F/7$$\"1LL$eRwX5$F3$\"1A$Q*=S7R8!#77$$\"1ML$3x%3yTF3$\"1h $G&[p%Qx\"FE7$$\"1nm\"z%4\\Y_F3$\"112AZoD$=#FE7$$\"1LLeR-/PiF3$\"1F5/Z YcQDFE7$$\"1++DcmpisF3$\"1UmCrW>zGFE7$$\"1MLe*)>VB$)F3$\"1$)4Ry-R+KFE7 $$\"1,+DJbw!Q*F3$\"1m<$*)*o1)[$FE7$$\"1nm;/j$o/\"!#9$\"1p4cck%*\\PFE7$ $\"1ML3_>jU6Fao$\"1d()4Ga\\_RFE7$$\"1++]i^Z]7Fao$\"1M!3Pm9,:%FE7$$\"1+ +](=h(e8Fao$\"1/)*)eN!zFao$ \"1VG)GwCUz%FE7$$\"1+]i!f#=$3#Fao$\"1jP?W0%Q\"[FE7$$\"1+](=xpe=#Fao$\" 1o=6Ae%*>[FE7$$\"1nm\"H28IH#Fao$\"1yT0x1'\\\"[FE7$$\"1n;zpSS\"R#Fao$\" 1ut1)HN:![FE7$$\"1ML3_?`(\\#Fao$\"1$p[Kd(*)yZFE7$$\"1M$e*)>pxg#Fao$\"1 zy%40]xu%FE7$$\"1+]Pf4t.FFao$\"11![vyz_r%FE7$$\"1LLe*Gst!GFao$\"1#Q-/+ 3bn%FE7$$\"1+++DRW9HFao$\"1u6$*oQ9IYFE7$$\"1++DJE>>IFao$\"1<>q'RLmy&QFE7$$\"1,++D>#[Z%Fao$\"1Cokvp72QFE7$$\"1nmT&G!e&e%Fao$\"1sY\"> tt(\\PFE7$$\"1MLL$)Qk%o%Fao$\"1])zb=[#*p$FE7$$\"1,]iSjE!z%Fao$\"1_M`Z5 AYOFE7$$\"1,]P40O\"*[Fao$\"1!HX8?7jf$FE7$$\"#]F($\"1EQ2hTiVNFE-%'COLOU RG6&%$RGBG$\"#5!\"\"F(F(-%+AXESLABELSG6$Q\"v6\"%!G-%%VIEWG6$;F(F^[l%(D EFAULTG" 1 2 0 1 0 2 9 1 4 2 1.000000 45.000000 45.000000 0 }}}} {EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 0 "" }}}}{MARK "1 0 0" 0 } {VIEWOPTS 1 1 0 1 1 1803 }