Next: Subsets of a group
Up: Conjugacy
Previous: Conjugacy
  Contents
  Index
- Prove that for
,
has a trivial center,
i.e.,
.
(HINT: Suppose
and
. Write
in its disjoint cycle form (see
equation (3.2) and Theorem 3.1.2). Consider the
following three cases:
- Case 1
has at least one
-cycle with
. Without
loss of generality, assume
in (3.2)
is such that
. Then calculate
and
.
- Case 2
- the disjoint cycle decomposition
of
has at least two transpositions (
-cycles),
say
in (3.2), i.e.,
.
Then calculate
and
.
- Case 3
; then calculate
and
- recall
.
In each case
and
we can ``calculate'' all we need to know by
computing the effect of each permutation (remember
permutation is a function) acting on
.)
- (a)
Suppose
and they have the same cycle structure.
Prove
(
means the relation of being conjugate).
(b)
Explain why there are as many conjugacy classes in
as there are partitions of
. (HINT:
Do it for
,
, first!)
- In
perform the indicated operations. Write the result
first as a product of disjoint cycles and
then in the 2-row form (2.1):
(a)
,
(b)
.
- In
, determine the number of conjugacy classes
and the number of permutations in each class.
(See problem 2 for Section 3.1.)
Next: Subsets of a group
Up: Conjugacy
Previous: Conjugacy
  Contents
  Index
David Joyner
2001-04-12