cin fails to inputcin object has type istream.
In fact, it is the only object of that type we've seen up until now. Other
than the >> operator, we haven't used it like we've used other
types; we never try any other operations.
Oddly enough, objects of type istream can be cast as type
bool, which means for example that they can be used in the
test condition of a loop or an if-statement. But what does
that mean?!?!? Let's look at an example:
int j, k;
k = 0;
cin >> j;
while( cin ) {
k = k + j;
cin >> j;
}
cout << k << endl;
Now what does this do? Well, if I run this program and enter
1 2 3 4;... it'll print out 10. What it's done is to compute the sum of the numbers entered, stopping at the ';' ... but why?
cin (or any other object of type
istream) fails to read in an object of the type you've
requested, it goes into a state that as a bool is
false. Otherwise, it translates into the bool
true.
So, in our loop:
int successfully
with cin >> j the evaluated expression
"cin" is of type istream and is cast to the
bool value true, meaning the loop continues.
int
but encounter a ';' instead, meaning that the read fails. So the loop
condition for the next iteration takes cin and casts it to
the bool value false, and the loop terminates.
In fact, in this state any subsequent attempts to read will fail,
too. This is a cool trick.
More often than not, we use the fact that the expression cin
>> j is an expression that evaluates to cin
(with the side effect of reading into the variable j), to
write the above more compactly as follows:
while(cin >> j) as follows:
cin >> j succeeds ...".int j, k;
k = 0;
while( cin >> j ) {
k = k + j;
}
cout << k << endl;
cin won't help us. However, we
can create an istream object that acts just like
cin except that it gets its character stream from a file
rather than a keyboard. So, let's do the same program as above, but
first let's create a file temp with the
input for our program.
#include <iostream>
#include <fstream>
using namespace std;
int main() {
// Create istream object that reads from file temp
ifstream fin("temp"); // note: fin has ifstream type
// Loop and add as long as more int's can be read
int j, k;
k = 0;
while( fin >> j ) { // note: quite similar to the above code except with cin vs. fin
k = k + j;
}
// Print out the sum k
cout << k << endl;
return 0;
}
A couple of comments follow.
When I say ifstream fin; it looks like I'm declaring an
object of type ifstream (and indeed I am!), and yet I
claimed to be creating an object of type istream, which is
it? Well ... it's both. As you get into more advanced programming, the
idea of subtypes will be important. For now I'll just say this:
cin and the fin we created are both of type
istream in the same way that "square" and "trapazoid" are
both in the category "quadrilateral" - they are subtypes of the type
quadrilateral.
Now, if you run this, it's only going to successfully open and read from
the file temp if temp is in the current
directory, i.e. the directory you were in when you launched the
program.
So what happens when your program doesn't find the file it's looking
for? Well, when you create fin to read from
temp, and temp does not exist, then
fin is in a state which, when cast as a bool, is
false. Thus, if we want to improve the program above so that it prints an
error message if the file temp cannot be found, we would do
return
1;" in main has the effect of exiting the program immediately, and
returning a non-zero value is the traditional way of indicating that there
was some kind of error.
ifstream fin("temp");
if( !fin ) {
cout << "File \"temp\" not found!" << endl;
return 1;
}
...
int for
example, and the file ends before istream object can read an
int, the istream object goes into an error state
again - i.e. casting it to a bool would result in the value
false.
So, if you had a file infile that simply consisted of
a bunch of numbers, nothing else, you could sum these numbers with the
code below (on the left).
If you prefer, we can use some of our shortcuts, namely that fin >>
k has the side effect of reading a new value into k, as
well as being an expression that has the value of the object fin
after the new value is read into k. See the code on the
right.
|
|
cin >>
c will ignore it (since it's just a whitespace), waiting for a
non-white-space character.
ifstream object that is open for
reading to a file. How are input file streams closed? Well, when the
ifstream object goes out of scope that variable dies,
and this closes the connection to the file. If another
ifstream object is created to read from the same file, it
starts over at the beginning.
fin
explicitly at any time with: fin.close()
cin, writing to a file is not much different
from writing to cout. First, you need to create an
object of type ostream like cout, but
which sends its output to a file. To do this, you declare a
variable of type ofstream.
#include <iostream>
#include <fstream>
using namespace std;
int main() {
// Create ostream object that writes to file outfile
ofstream fout("outfile");
// Write 1 through 10 on separate lines
int i;
i = 1;
while( i <= 10 ) {
fout << i << endl;
i = i + 1;
}
return 0;
}
You don't really have the issue of checking to see if the file is
found, since you're trying to create a new file. If there is file
of that name already there, it gets obliterated ... oops! A fully
featured program might warn the user of this. Can you think of
how you might check whether the file outfile already
exists?
name is a string object with
the name of the file you'd like to open, then
ifstream fin(name.c_str());or
ifstream fin; fin.open(name.c_str());opens an input stream to that file, not
ifstream fin(name),
like you'd hope.
The deal is this:
iostream stuff expects a C-style
string, not a C++ string object. When you have a C++
string object s, then s.c_str()
evaluates to the C-style version of the same string.