slope = (y1 - y2) / (x1 - x2)For the purists among you, you may assume that the line is not vertical.
We already know the basic structure here, just our usual "main" skeleton. |
int main() { return 0; } |
Let's add in comments outlining the basic process for solving this problem. |
int main() { // Read first point // Read second point // Compute the slope // Print out slope return 0; } |
Reading in a point means reading in a value for x1 and y1. First let's read in x1. First we declare variable for the value, then we ask the user for the value, then we read the value! |
// Read first point double x1; cout << "Enter x1: "; cin >> x1; double y1; cout << "Enter y1: "; cin >> y1; |
This is easily extended for the other values. |
int main() { // Read first point double x1; cout << "Enter x1: "; cin >> x1; double y1; cout << "Enter y1: "; cin >> y1; // Read second point double x2; cout << "Enter x2: "; cin >> x2; double y2; cout << "Enter y2: "; cin >> y2; // Compute the slope // Print out slope return 0; } |
To compute the slope, we first declare a variable to contain the slope, and then we compute its value. |
// Compute the slope double slope; slope = (y1 - y2) / (x1 - x2); |
All we have to do now is print out the answer, which is old hat. |
// Print out slope cout << "The slope is: "; cout << slope << endl; |
And now we have a complete solution!