/*************************************************** Date conversion program Write a program that reads in a date in the form <month name> <day>, <year> (for example, "January 12, 2001"), and prints out the same date in the form <month>/<day/<last year digits> (for example, "01/12/01"). ***************************************************/ #include <iostream> #include <string> using namespace std; int main() { // Read date string s; int y, year, month, day; char c; cin >> s >> day >> c >> y; // compute year number year = y % 100; // compute month number if (s == "January") month = 1; else if (s == "February") month = 2; else if (s == "March") month = 3; else if (s == "April") month = 4; else if (s == "May") month = 5; else if (s == "June") month = 6; else if (s == "July") month = 7; else if (s == "August") month = 8; else if (s == "September") month = 9; else if (s == "October") month = 10; else if (s == "November") month = 11; else if (s == "December") month = 12; // print month if (month < 10) cout << "0"; cout << month << "/"; // print day if (day < 10) cout << "0"; cout << day << "/"; // print year if (year < 10) cout << "0"; cout << year << endl; return 0; }