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For this assignment you will want to consult the C++ operator associativity/precedence table.

1. [10pts] For each of the below, circle the correctly parenthesized version of the expression and circle "precedence" or "associativity" as appropriate.
   
   
   1. x + y * z evaluates as (x + y) * z OR x + (y * z) due to: precedence associativity
   2. x > y + z evaluates as (x > y) + z OR x > (y + z) due to: precedence associativity
   3. cin >> x >> y evaluates as (cin >> x) >> y OR cin >> (x >> y) due to: precedence associativity
   4. x = y = 1 evaluates as (x = y) = 1 OR x = (y = 1) due to: precedence associativity
   5. cin >> x = y evaluates as (cin >> x) = y OR cin >> (x = y) due to: precedence associativity
2. [10pts] Assume the following delcarations fill in the table. New Note: each expression should be taken as independent. I.e. if one expression modifies some variable values, those modifications do not carry over to the next expression.
   

   int n = 5;
   double x = 1.5;
   char c = 'R';
   

   expression	type	value
   n = 2
   n == 2
   c < 200
   1 != x
   n*x
3. [5pts] Explain why 1 < x < 10 always returns true no matter what x is.
4. [75pts] A year is a leap year if it is evenly divisible by 4, Except that years that are evenly divisible by 100 are not leap years unless they are evenly divisible by 400. Clear? For example:

   Year	divisible by 4?	divisible by 100?	divisible by 400?	Is leap year?
   703	no	no	no	not leap year
   704	yes	no	no	leap year
   700	yes	yes	no	not leap year
   800	yes	yes	yes	leap year

   Write a program that reads a year and prints out (correctly!) Is Leap Year or Is Not Leap Year. Here are two example runs.

   $ ./hw
   Enter year: 703
   Is Not Leap Year
   $ ./hw
   Enter year: 704
   Is Leap Year

   Important: For those of you who already know about &&, || or !, do not use them!